There are 2 adjacent bus stops. A person A wants to reach a particular place by travelling by bus. For the destination, buses of 3 routes stop at 1st stop and bus of 1 route stops at other stop. Distance between 2 bus stops is 120 feet, At what distance should A stand from 1st bus stop.
Solution:
Total no. of bus routes for the particular destination = 4.
Buses of no. of bus routes stooping at 1st stop = 3
Therefore, Probability that A will get bus from 1st stop is 3/4.
{Had there been no bus stopping at 2nd bus stop for his destination he would have stopped at 1st bus stop only.}
He should stand nearer to 1st bus stop. So distance from 1st stop will be = (1-3/4)*120= (1/4)*120 =30 feet from 1st bus stop.
Solution:
Total no. of bus routes for the particular destination = 4.
Buses of no. of bus routes stooping at 1st stop = 3
Therefore, Probability that A will get bus from 1st stop is 3/4.
{Had there been no bus stopping at 2nd bus stop for his destination he would have stopped at 1st bus stop only.}
He should stand nearer to 1st bus stop. So distance from 1st stop will be = (1-3/4)*120= (1/4)*120 =30 feet from 1st bus stop.
