1) Take any point B.
2) Draw a horizontal line.
3) Take any point D say to right of B, say at a distance 5 cm from B.
4) Take any radius more than half
of BD say 3 cm and draw arcs with center B & D on upper part of seg BD.
5) Name the point of intersection of arcs as A.
6) Draw a ray from D to A so that it extends beyond A, above B and to the left of B.
7) With point A as center and radius equal to AD, draw an arc PQ to cut the ray DA at point C.
8) Join C & B.
9) Angle CBD = 90 degrees. i.e. CB is perpendicular to BD.
This construction is based on following properties and theorem respectively:
(1) In right angled triangle, median on hypotenuse is half the hypotenuse.
(2) Angle inscribed in a semi-circle is 90 degrees
(1) In right angled triangle, median on hypotenuse is half the hypotenuse.
(2) Angle inscribed in a semi-circle is 90 degrees
