Friday, 29 November 2019

Square root by long division method

4299 18481401 99999999 OK OK OK OK OK OK Step1
4 2 9 8 9 9 2 0 0 0 Step 3
Step 1 4 18 48 14 1 0 0 0 1 1 1 a= 42
+ 4 - 16 2 4 2 b= 9 10
Step 2 8 2 2 48 3 9 3 20a 840 10.01667
+ + 2 248 4 16 4 b= 9
Step 3 84 9 84 Tally - 164 5 25 5 20a +b 849
+ 9 84 14 6 36 6 (20a+b)b 7641 OK
Step 4 858 8 858 Tally 8414 7 49 7
+ 8 - 7641 8 64 8 Step 4
Step 5 8596 9 773 1 9 81 9 a= 429
+ 9 77301 100 b= 8 9
Step 6 85978 9 - 68768 Step2 20a 8580 9.009441
+ 9 8533 0 a= 4 b= 8
Step 7 859798 2 853300 b= 2 3 20a +b 8596
2 - 773802 20a 80 3.1 (20a+b)b 68768 OK
8597984 79498 0 b= 2
=2*square root 7949800 20a +b 82
8597984 - 7738182 (20a+b)b 164 OK Step 5
= 2 x  4298992 211618 0 a= 4298
0 21161800 b= 9 9
Correct Answer - 17195968 20a 85960 9.92671
3965832 b= 9
20a +b 85978
4299 (20a+b)b 773802 OK

Step 6 Step 7
a= 42989 a= 429899
b= 9 9 b= 2 2
20a 859780 9.246319 20a 8597980 2.461253
b= 9 b= 2
20a +b 859798 20a +b 8597984
(20a+b)b 7738182 OK (20a+b)b 17195968 OK

compiled trick


Wednesday, 6 November 2019

Length of angle bisector of right angle in right angled triangle


In triangle BCA, /_ C =90॰ BC=a CA=b.  Bisector of /_C meets BA at D. Find length of CD. (Hint: draw BF perpendicular on CD.)
1) Find area of the triangle BCA.
2) Find hypotenuse BA.
3)Find length of perpendicular CF on hypo. BA
4) Find BD and DA by angle bisector property / theorem.
5) Find area of triangle BCD.
6) Find BF = a sin 45॰
7) From area of triangle BCD find CD. using CD as base and BF as height.


(ab x sq root 2)/(a+b)

Tuesday, 5 November 2019

10 SSC 2020 onward pattern Q. 5 create your two own questions

Use 1+tan sq A= sec sq A to make question.
Two rational numbers are such that their difference and reciprocal of their sums is same and equal to k. Find the numbers.