3 successive natural numbers can and will always be sides of a triangle EXCEPT 1ST triplet i.e. 1.2 and 3.
Proof:
Let a, a+1 and a+2 be 3 sides of triangle. Sum of any 2 sides of a triangle is greater than 3rd side. So,
1. a+a+1 > a+2 i.e. a+1>2 so, a >1 therefore a>(1)
2. a+1+a +2 > a So, 2a+3>a, then a> (-3)
3. a+a+2 > a+1 So, a > -1
Selecting highest of the numbers from R.H.Sides of above inequalities so that other 2 conditions are satisfied. So a>1.
Examples: 2,3,4
3,4,5 (only right angled triangle)
4,5,6
5,6,7
12,13,14
These will always form scalene triangle. ( the 3 numbers being different)
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